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0=-4x^2+20x-15
We move all terms to the left:
0-(-4x^2+20x-15)=0
We add all the numbers together, and all the variables
-(-4x^2+20x-15)=0
We get rid of parentheses
4x^2-20x+15=0
a = 4; b = -20; c = +15;
Δ = b2-4ac
Δ = -202-4·4·15
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{10}}{2*4}=\frac{20-4\sqrt{10}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{10}}{2*4}=\frac{20+4\sqrt{10}}{8} $
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